to()

A.to(a)

From sequence A, generate a sequence composed of the first a members; when a<0, get members from the (A.len()+1+a)^th one to the (A.len())^th one

A.to(a,b)

From the sequence A, generate a sequence composed of the members from the ath to the bth. If omitting a, then start from the first member by default; if omitting b, get all members of A, that is A.len(), by default, and in this case the comma must not be omitted; if a>b, find the members backwards; members of the newly-generated sequence are ordered in an opposite direction relative to their original order

A

A sequence

a

The integer specifying the starting position

b

The integer specifying the ending position

[1,5,2,6,8].to(2,3)

Return sequence [5,2].

[1,5,2,6,8].to(3,2)

Return sequence [2,5].

[1,5,2,6,8].to(2)

Return sequence [1,5].

[1,5,2,6,8].to(-2)

Return sequence [6,8].

to(a,b)

Generate a sequence composed of continuous integers between a and b.

to(n) 

Generate a sequence composed of continuous integers from 1 to n.

a

The starting integer.

b

The ending integer.

n

n>0.

@s

Generate a sequence composed of continuous b integers starting from a. If b is less than 0, generate the sequence backward sequentially in descending order.

A

1

=to(3,7)

[3,4,5,6,7]

2

=to(5,3)

[5,4,3]

3

=to(-2,3)

[-2,-1,0,1,2,3]

4

=to(3,-2)

[3,2,1,0,-1,-2]

5

=to@s(3,4)

[3,4,5,6]

6

=to@s(3,-2)

[3,2]

7

=to(10)

[1,2,3,4,5,6,7,8,9,10]